Parabola 1 Question 7

7. Axis of a parabola is y=x and vertex and focus are at a distance 2 and 22 respectively from the origin. Then, equation of the parabola is

(2006, 3M)

(a) (xy)2=8(x+y2)

(b) (x+y)2=2(x+y2)

(c) (xy)2=4(x+y2)

(d) (x+y)2=2(xy+2)

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Answer:

Correct Answer: 7. (a)

Solution:

  1. Since, distance of vertex from origin is 2 and focus is 22.

V(1,1) and F(2,2) (i.e. lying on y=x )

where, length of latusrectum

=4a=42[a=2]

By definition of parabola

where, PN is length of perpendicular upon x+y2=0, i.e. tangent at vertex

(xy)22=42x+y22(xy)2=8(x+y2)



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