Complex Numbers 5 Question 6

6.

If ω(1) be a cube root of unity and (1+ω2)n=(1+ω4)n, then the least positive value of n is

(a) 2

(b) 3

(c) 5

(d) 6

(2004, 1M)

Show Answer

Answer:

Correct Answer: 6. (b)

Solution:

  1. Given, (1+ω2)n=(1+ω4)n

(ω)n =(ω2)n

[ω3=1 and 1+ω+ω2=0]

ωn =1

n =3 is the least positive value of n.



NCERT Chapter Video Solution

Dual Pane