Circle 5 Question 7

7. The equations of the tangents drawn from the origin to the circle $x^{2}+y^{2}+2 r x+2 h y+h^{2}=0$, are

$(1988,2 M)$

(a) $x=0$

(b) $y=0$

(c) $\left(h^{2}-r^{2}\right) x-2 r h y=0$

(d) $\left(h^{2}-r^{2}\right) x+2 r h y=0$

Assertion and Reason

For the following questions, choose the correct answer from the codes (a), (b), (c) and (d) defined as follows.

(a) Statement I is true, Statement II is also true;

Statement II is the correct explanation of Statement I.

(b) Statement I is true, Statement II is also true; Statement II is not the correct explanation of Statement I

(c) Statement I is true; Statement II is false

(d) Statement I is false; Statement II is true

Show Answer

Answer:

Correct Answer: 7. $(a, c)$

Solution:

  1. Since, tangents are drawn from origin. So, the equation of tangent be $y=m x$.

$\Rightarrow$ Length of perpendicular from origin $=$ radius

$$ \begin{aligned} & \Rightarrow & \frac{|m r+h|}{\sqrt{m^{2}+1}} & =r \\ \Rightarrow & & m^{2} r^{2}+h^{2}+2 m r h & =r^{2}\left(m^{2}+1\right) \\ & \Rightarrow & m & =\frac{r^{2}-h^{2}}{2 r h}, m=\infty \end{aligned} $$

$\therefore$ Equation of tangents are $y=\frac{r^{2}-h^{2}}{2 r h} x, x=0$

Therefore (a) and (c) are the correct answers.



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