Circle 5 Question 21

21. Lines 5x+12y10=0 and 5x12y40=0 touch a circle C1 of diameter 6 . If the centre of C1 lies in the first quadrant, find the equation of the circle C2 which is concentric with C1 and cuts intercepts of length 8 on these lines.

(1986, 5M)

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Answer:

Correct Answer: 21. (x5)2+(y2)2=52

Solution:

  1. Since, 5x+12y10=0 and 5x12y40=0 are both perpendicular tangents to the circle C1.

OABC forms a square.

Let the centre coordinates be (h,k), where,

OC=OA=3 and OB=62|5h+12k10|13=3 and |5h+12k40|13=3

5h+12k10=±39 and 5h12k40=±39 on solving above equations. The coordinates which lie in I quadrant are (5,2).

Centre for C1(5,2)

To obtain equation of circle concentric with C1 and making an intercept of length 8 on 5x+12y=10 and 5x12y=40 Required equation of circle C2 has centre (5,2) and radius 5 is (x5)2+(y2)2=52



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