SATHEE: 3D Geometry 3 Question 56

3D Geometry 3 Question 56

####56. The distance of the point $(1, 1, 1)$ from the plane passing through the point $(- 1, - 2, - 1)$ and whose normal is perpendicular to both the lines $L_{1}$ and $L_{2}$ , is

(a) $2 / \sqrt{75}$ unit

(b) $7 / \sqrt{75}$ unit

(d) $23 / \sqrt{75}$ units

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Answer:

Correct Answer: 56. (c)

Solution:

The equation of the plane passing through the point $(- 1, - 2, - 1)$ and whose normal is perpendicular to both the given lines $L_{1}$ and $L_{2}$ may be written as

$(x + 1) + 7 (y + 2) - 5 (z + 1) = 0 \Rightarrow x + 7 y - 5 z + 10 = 0$

The distance of the point $(1, 1, 1)$ from the plane

$= | \frac{1 + 7 - 5 + 10}{\sqrt{1 + 49 + 25}} | = \frac{13}{\sqrt{75}} units$

3D Geometry 3 Question 56

Answer:

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3D Geometry 3 Question 56

Answer:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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