Surface Chemistry - Result Question 5
####5. Match the catalysts Column I with products Column II.
(2019 Main, 9 April I)
| Column I (Catalyst) | Column II (Product) | ||
|---|---|---|---|
| (A) | $V _2 O _5$ | (i) | Polyethlyene |
| (B) | $TiCl _4 / Al(Me) _3$ | (ii) | Ethanal |
| (C) | $PbCl _2$ | (iii) | $H _2 SO _4$ |
| (D) | Iron oxide | (iv) | $NH _3$ |
(a) (A)-(ii), (B)-(iii), (C)-(i), (D)-(iv)
(b) (A)-(iv), (B)-(iii), (C)-(ii), (D)-(i)
(c) (A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)
(d) (A)-(iii), (B)-(iv), (C)-(i), (D)-(ii)
Show Answer
Answer:
Correct Answer: 5. (b)
Solution:
- Correct match is
(A) $\rightarrow$ (iii); (B) $\rightarrow$ (i); (C) $\rightarrow$ (ii); (D) $\rightarrow$ (iv)
(i) $TiCl _4+AlCl _3$ (Ziegler- Natta catalyst) is used to prepare polyethylene from ethene.
(ii) $V _2 O _5$ (Vanadium pentoxide) is used as catalyst to prepare $H _2 SO _4$ from contact process. Reaction involved is
$$ 2 SO _2(g)+O _2(g) \xrightarrow{V _2 O _5} 2 SO _3(g) $$
It is the key step in the manufacture of $H _2 SO _4$.
(iii) Fe (Iron) is used as catalyst in Haber’s process for the manufacture of ammonia.
$$ N _2(g)+3 H _2(g) \stackrel{Fe(s)}{\longrightarrow} 2 NH _3(g) $$
(iv) $Pd$ (Palladium) is used to prepare ethanal. Reaction involved is
$$ H _2 C=CH _2+O _2 \xrightarrow[H _2 O]{PdCl _2 / CuCl _2} CH _3 CHO $$
This reaction is also known as Wacker’s process.
