Surface Chemistry - Result Question 5

####5. Match the catalysts Column I with products Column II.

(2019 Main, 9 April I)

Column I (Catalyst) Column II (Product)
(A) $V _2 O _5$ (i) Polyethlyene
(B) $TiCl _4 / Al(Me) _3$ (ii) Ethanal
(C) $PbCl _2$ (iii) $H _2 SO _4$
(D) Iron oxide (iv) $NH _3$

(a) (A)-(ii), (B)-(iii), (C)-(i), (D)-(iv)

(b) (A)-(iv), (B)-(iii), (C)-(ii), (D)-(i)

(c) (A)-(iii), (B)-(i), (C)-(ii), (D)-(iv)

(d) (A)-(iii), (B)-(iv), (C)-(i), (D)-(ii)

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Answer:

Correct Answer: 5. (b)

Solution:

  1. Correct match is

(A) $\rightarrow$ (iii); (B) $\rightarrow$ (i); (C) $\rightarrow$ (ii); (D) $\rightarrow$ (iv)

(i) $TiCl _4+AlCl _3$ (Ziegler- Natta catalyst) is used to prepare polyethylene from ethene.

(ii) $V _2 O _5$ (Vanadium pentoxide) is used as catalyst to prepare $H _2 SO _4$ from contact process. Reaction involved is

$$ 2 SO _2(g)+O _2(g) \xrightarrow{V _2 O _5} 2 SO _3(g) $$

It is the key step in the manufacture of $H _2 SO _4$.

(iii) Fe (Iron) is used as catalyst in Haber’s process for the manufacture of ammonia.

$$ N _2(g)+3 H _2(g) \stackrel{Fe(s)}{\longrightarrow} 2 NH _3(g) $$

(iv) $Pd$ (Palladium) is used to prepare ethanal. Reaction involved is

$$ H _2 C=CH _2+O _2 \xrightarrow[H _2 O]{PdCl _2 / CuCl _2} CH _3 CHO $$

This reaction is also known as Wacker’s process.



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