SATHEE: States of Matter - Result Question 32

States of Matter - Result Question 32

####32. The value of van der Waals’ constant $a$ for the gases $O_{2}, N_{2}$ , $N H_{3}$ and $C H_{4}$ are $1.360, 1.390, 4.170$ and $2.253 L^{2}$ atm $m o l^{- 2}$ respectively. The gas which can most easily be liquefied is

(a) $O_{2}$

(b) $N_{2}$

(d) $C H_{4}$

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Solution:

The ease of liquefication of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant $a$ . Hence, higher the value of $a$ , greater the intermolecular force of attraction, easier the liquefication.

In the present case, $N H_{3}$ has highest $a$ , can most easily be liquefied.

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States of Matter - Result Question 32

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