States of Matter - Result Question 32
####32. The value of van der Waals’ constant $a$ for the gases $O _2, N _2$, $NH _3$ and $CH _4$ are $1.360,1.390,4.170$ and $2.253 L^{2}$ atm $mol^{-2}$ respectively. The gas which can most easily be liquefied is
(a) $O _2$
(b) $N _2$
(c) $NH _3$
(d) $CH _4$
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Solution:
- The ease of liquefication of a gas depends on their intermolecular force of attraction which in turn is measured in terms of van der Waals’ constant $a$. Hence, higher the value of $a$, greater the intermolecular force of attraction, easier the liquefication.
In the present case, $NH _3$ has highest $a$, can most easily be liquefied.
