SATHEE: Some Basic Concepts of Chemistry

Some Basic Concepts of Chemistry - Result Question 30

####30. A student performs a titration with different burettes and finds titrate values of $25.2 m L, 25.25 m L$ , and $25.0 m L$ . The number of significant figures in the average titrate value is

(2010)

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Solution:

Number of molecules present in $36 g$ of water

$= \frac{36}{18} \times N_{A} = 2 N_{A}$

Number of molecules present in $28 g$ of $C O = \frac{28}{28} \times N_{A} = N_{A}$

Number of molecules present in $46 g o f_{2} H_{5} O H = \frac{46}{46} \times N_{A} = N_{A}$

Here, $N_{A}$ is Avogadro’s number. Hence, $36 g$ of water contain the largest $(2 N_{A})$ number of molecules.

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Some Basic Concepts of Chemistry - Result Question 30

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