Some Basic Concepts of Chemistry - Result Question 30
####30. A student performs a titration with different burettes and finds titrate values of $25.2 mL, 25.25 mL$, and $25.0 mL$. The number of significant figures in the average titrate value is
(2010)
Subjective Questions
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Solution:
- Number of molecules present in $36 g$ of water
$$ =\frac{36}{18} \times N _A=2 N _A $$
Number of molecules present in $28 g$ of $CO=\frac{28}{28} \times N _A=N _A$
Number of molecules present in $46 g of _2 H _5 OH=\frac{46}{46} \times N _A=N _A$
Here, $N _A$ is Avogadro’s number. Hence, $36 g$ of water contain the largest $\left(2 N _A\right)$ number of molecules.
