Qualitative Analysis - Result Question 4

####4. In Carius method of estimation of halogens $250 mg$ of an organic compound gave $141 mg$ of $AgBr$. The percentage of bromine in the compound is (atomic mass $Ag=108, Br=80$ )

(a) 24

(b) 36

(c) 48

(d) 60

(2015 Main)

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Answer:

Correct Answer: 4. (a)

Solution:

  1. Given, Weight of organic compound $=250 mg$

Weight of $AgBr=141 mg$

$\therefore$ According to formula of $\text{\%}$ of bromine by Carius method

$\text{\%}$ of $Br=\frac{\text { Atomic weight of } Br}{\text { Molecular weight of } AgBr}$

$$ \begin{aligned} & \times \frac{\text { Weight of } AgBr}{\text { Weight of organic bromide }} \times 100 \\ \therefore \text{\%} \text { of } Br=\frac{80}{188} \times \frac{141}{250} \times 100 & =\frac{1128000}{47000}=24 \text{\%} \end{aligned} $$



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