Qualitative Analysis - Result Question 4
####4. In Carius method of estimation of halogens $250 mg$ of an organic compound gave $141 mg$ of $AgBr$. The percentage of bromine in the compound is (atomic mass $Ag=108, Br=80$ )
(a) 24
(b) 36
(c) 48
(d) 60
(2015 Main)
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Solution:
- Given, Weight of organic compound $=250 mg$
Weight of $AgBr=141 mg$
$\therefore$ According to formula of $%$ of bromine by Carius method
$%$ of $Br=\frac{\text { Atomic weight of } Br}{\text { Molecular weight of } AgBr}$
$$ \begin{aligned} & \times \frac{\text { Weight of } AgBr}{\text { Weight of organic bromide }} \times 100 \ \therefore % \text { of } Br=\frac{80}{188} \times \frac{141}{250} \times 100 & =\frac{1128000}{47000}=24 % \end{aligned} $$
