Chemical Bonding - Result Question 67

####42. The ion that is isoelectronic with $CO$ is

$(1982,1 M)$

(a) $CN^{-}$

(b) $O _2^{+}$

(c) $O _2^{-}$

(d) $N _2^{+}$

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Solution:

  1. CO has a total of 14 electrons and $CN^{-}$also has 14 electrons.

$$ C\left(6 e^{-}\right)+N\left(7 e^{-}\right)+e^{-} \longrightarrow CN^{-}\left(14 e^{-}\right) $$



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