Chemical Bonding - Result Question 67
####42. The ion that is isoelectronic with $CO$ is
$(1982,1 M)$
(a) $CN^{-}$
(b) $O _2^{+}$
(c) $O _2^{-}$
(d) $N _2^{+}$
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Solution:
- CO has a total of 14 electrons and $CN^{-}$also has 14 electrons.
$$ C\left(6 e^{-}\right)+N\left(7 e^{-}\right)+e^{-} \longrightarrow CN^{-}\left(14 e^{-}\right) $$