SATHEE: Chemical Bonding - Result Question 65

Chemical Bonding - Result Question 65

####40. On hybridisation of one $s$ and one $p$ -orbital we get

(a) two mutually perpendicular orbitals

$(1984, 1 M)$

(b) two orbitals at $180^{\circ}$

(d) three orbitals in a plane

Show Answer

Solution:

Hybridisation of one ’ $s$ ’ and one ’ $p$ ’ orbitals gives two $s p$ hybrid orbitals oriented linearly at $180^{\circ}$ .

$s + p ⟶ 2 s p hybrid orbitals$

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Chemical Bonding - Result Question 65

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