Chemical Bonding - Result Question 65

####40. On hybridisation of one $s$ and one $p$-orbital we get

(a) two mutually perpendicular orbitals

$(1984,1 M)$

(b) two orbitals at $180^{\circ}$

(c) four orbitals directed tetrahedrally

(d) three orbitals in a plane

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Solution:

  1. Hybridisation of one ’ $s$ ’ and one ’ $p$ ’ orbitals gives two $s p$ hybrid orbitals oriented linearly at $180^{\circ}$.

$$ s+p \longrightarrow 2 s p \text { hybrid orbitals } $$



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