Atomic Structure - Result Question 66

####42. Correct set of four quantum numbers for the valence (outermost) electron of rubidium $(Z=37)$ is

(a) $5,0,0,+\frac{1}{2}$

(b) $5,1,0,+\frac{1}{2}$

(c) $5,1,1,+\frac{1}{2}$

(d) $6,0,0,+\frac{1}{2}$

$(1984,1 M)$

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Answer:

Correct Answer: 42. $(a, d)$

Solution:

  1. The valence shell configuration of Rubidium $(Rb)$ is

$$ [Kr] 5 s^{1} \quad n=5, l=0, m=0, s=+\frac{1}{2} \quad \text { or } \quad-\frac{1}{2} $$



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