Atomic Structure - Result Question 66
####42. Correct set of four quantum numbers for the valence (outermost) electron of rubidium $(Z=37)$ is
(a) $5,0,0,+\frac{1}{2}$
(b) $5,1,0,+\frac{1}{2}$
(c) $5,1,1,+\frac{1}{2}$
(d) $6,0,0,+\frac{1}{2}$
$(1984,1 M)$
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Answer:
Correct Answer: 42. $(a, d)$
Solution:
- The valence shell configuration of Rubidium $(Rb)$ is
$$ [Kr] 5 s^{1} \quad n=5, l=0, m=0, s=+\frac{1}{2} \quad \text { or } \quad-\frac{1}{2} $$
