Atomic Structure - Result Question 57

####33. The correct set of quantum numbers for the unpaired electron of chlorine atom is

$(1989,1 M)$

$\boldsymbol{n}$ $\boldsymbol{l}$ $\boldsymbol{m}$ $\boldsymbol{n}$ $\boldsymbol{l}$ $\boldsymbol{m}$
(a) 2 1 0 (b) 2 1 1
(c) 3 1 1 (d) 3 0 0
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Answer:

Correct Answer: 33. (c)

Solution:

  1. $Cl(17)=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$

The last, unpaired electron has, $n=3, l=1(p)$ and $m$ can have any of the three value $(-1,0,+1)$.



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