Atomic Structure - Result Question 57
####33. The correct set of quantum numbers for the unpaired electron of chlorine atom is
$(1989,1 M)$
| $\boldsymbol{n}$ | $\boldsymbol{l}$ | $\boldsymbol{m}$ | $\boldsymbol{n}$ | $\boldsymbol{l}$ | $\boldsymbol{m}$ | ||
|---|---|---|---|---|---|---|---|
| (a) | 2 | 1 | 0 | (b) 2 | 1 | 1 | |
| (c) | 3 | 1 | 1 | (d) 3 | 0 | 0 |
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Answer:
Correct Answer: 33. (c)
Solution:
- $Cl(17)=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$
The last, unpaired electron has, $n=3, l=1(p)$ and $m$ can have any of the three value $(-1,0,+1)$.
