Aromatic Aldehydes Ketones and Acids - Result Question 17

####21. In the Cannizzaro’s reaction given below :

$$ 2 Ph-CHO \xrightarrow{KOH} Ph-CH _2 OH+PhCO _2^{-} $$

The slowest step is

$(1996,1 M)$

(a) the attack of $-OH$ at the carbonyl group

(b) the transfer of hydride to the carbonyl group

(c) the abstraction of proton from the carboxylic acid

(d) the deprotonation of $Ph-CH _2 OH$

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Answer:

Correct Answer: 21. (b)

Solution:

21.



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