Aromatic Aldehydes Ketones and Acids - Result Question 17
####21. In the Cannizzaro’s reaction given below :
$$ 2 Ph-CHO \xrightarrow{KOH} Ph-CH _2 OH+PhCO _2^{-} $$
The slowest step is
$(1996,1 M)$
(a) the attack of $-OH$ at the carbonyl group
(b) the transfer of hydride to the carbonyl group
(c) the abstraction of proton from the carboxylic acid
(d) the deprotonation of $Ph-CH _2 OH$
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Answer:
Correct Answer: 21. (c)
Solution:
21.
