wave-optics Question 24

Question: Q. 9. Answer the following questions :

(i) In a double slit experiment using light of wavelength 600 nm, the angular width of the fringe formed on a distant screen is 0.1. Find the spacing between the two slits.

(ii) Light of wavelength 5000\AA propagating in air gets partly reflected from the surface of water. How will the wavelengths and frequencies of the reflected and refracted light be affected?

A [Delhi I, II, III 2015]

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Solution:

Ans. Finding the spacing between two slits 1 Effect on wavelength and frequency of reflected and refracted width light.

(i) Angular width of fringes :

θ=λd

where, d= separation between two slits

Here θ=01=01×π180 radian

d=600×109×1800.1×πm =3.43×104 m =0.34 mm

(ii) For Reflected light :

Wavelength remains same

Frequency remains same

For Refracted light :

Wavelength decreases

Frequency remains same

[CBSE Marking Scheme 2015]

Detailed Answer :

(b) Incident ray Reflected ray

we know that frequency of light is same in all media Thus,

f=vλ=3.0×1085000×1010 =0.6×10+15 =0.6×1015 Hz

If wavelength in air is Misplaced & that in water is λ2.

μ2=v2v1=λ2λ1 λ2=λ1(μ1μ2) λ2=5000(μ1μ2)\AA

Wavelength of refracted ray decreases by a factor of (μ1μ2) while wavelength of reflected ray may remains same.

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