SATHEE: semiconductor-electronics--materials-devices-and-simple-circuits Question 14

Semiconductor Electronics Materials Devices And Simple Circuits

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semiconductor-electronics--materials-devices-and-simple-circuits Question 14

Question: Q. 2. A $220 \mathrm{~V}$ A.C. supply is connected between points $A$ and $B$ in Figure. What will be the potential difference $V$ across the capacitor?

B (a) $220 \mathrm{~V}$. (b) $110 \mathrm{~V}$. (c) $0 \mathrm{~V}$. (d) $220 \sqrt{2} \mathrm{~V}$.

[NCERT Exemplar]

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Solution:

Ans. Correct option:(d)

Explanation. Dotential difference across capacitors will be peak voltage when diode is in forward bias. Diode will be in forward bias when end $A$ is at positive potential of cycle.

So potential at $C=$ peak value of

$V=V_{r m s} \sqrt{2}=220 \sqrt{2} \mathrm{~V}$.

Semiconductor Electronics Materials Devices And Simple Circuits

semiconductor-electronics--materials-devices-and-simple-circuits Question 14

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Semiconductor Electronics Materials Devices And Simple Circuits

semiconductor-electronics--materials-devices-and-simple-circuits Question 14

Very Short Answer TypeQuestions

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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