Question: Q. 2. A $220 \mathrm{~V}$ A.C. supply is connected between points $A$ and $B$ in Figure. What will be the potential difference $V$ across the capacitor?
B (a) $220 \mathrm{~V}$. (b) $110 \mathrm{~V}$. (c) $0 \mathrm{~V}$. (d) $220 \sqrt{2} \mathrm{~V}$.
[NCERT Exemplar]
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Solution:
Ans. Correct option:(d)
Explanation. Dotential difference across capacitors will be peak voltage when diode is in forward bias. Diode will be in forward bias when end $A$ is at positive potential of cycle.
So potential at $C=$ peak value of
$V=V_{r m s} \sqrt{2}=220 \sqrt{2} \mathrm{~V}$.
