semiconductor-electronics--materials-devices-and-simple-circuits Question 13
Question: Q. 1. In Figure, assuming the diodes to be ideal,
(a) $D_{1}$ is forward biased and $D_{2}$ is reverse biased and hence current flows from $A$ to $B$
(b) $D_{2}$ is forward biased and $D_{1}$ is reverse biased and hence no current flows from $B$ to $A$ and vice versa.
(c) $D_{1}$ and $D_{2}$ are both forward biased and hence current flows from $A$ to $B$.
(d) $D_{1}$ and $D_{2}$ are both reverse biased and hence no current flows from $A$ to $B$ and vice versa.
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Solution:
Ans. Correct option : (b)
Explanation : In circuit, $A$ is at $-10 \mathrm{~V}$ and $B$ is at $0 \mathrm{~V}$. So $B$ is positive than $A$. So $\mathrm{D}{2}$ is in forward bias and $D{1}$ is in reverse bias so no current flows from $A$ to $B$ or $B$ to $A$.
