ray-optics-and-optical-instruments Question 33

Question: Q. 10. A ray of light, incident on an equilateral glass prism (μg=3) moves parallel to the base line of the prism inside it. Find the angle of incidence for this ray.

A [Delhi I, II, III 2012]

From the diagram, r=30

Also

n21=sinisinr

or,

3=sinisin30

or, sini=3×12

or, i=60

[CBSE Marking Scheme 2012]

Short Answer Type Questions-II

(3 marks each)

Q. 1. (i) Show using a proper diagram how unpolarized light can be linearly polarised by reflection from a transparent glass surface.

(ii) The figure shows a ray of light falling normally on on the face AB of an equilateral glass prism having refractive index 32, placed in water of refractive index 43. Will this ray suffer total internal reflection on striking the face AC ? Justify your answer.

A [CBSE 2018, 2012]

Show Answer

Solution:

Ans. (i) The diagram, showing polarisation by reflection is as shown. [Here the reflected and refracted rays are at right angle to each other.

r=(π2iB) μ=(siniBsinr=taniB)

Thus light gets totally polarised by reflection when it is incident at an angle iB (Brewster’s angle), where iB=tan1μ

(ii) The angle of incidence, of the ray, on striking the face AC is i=60 (as from figure)

Also, relative refractive index of glass, with respect to the surrounding water, is

For total internal reflection, the required critical angle, in this case, is given by

siniC=1μ=890.89

i<iC

Hence the ray would not suffer total internal reflection on striking the face AC.

[The student may just write the two conditions needed for total internal reflection without analysis of the given case.

The student may be awarded (1/2+1/2) mark in such a case.

[CBSE Marking Scheme 2018]

AT Q. 2. (i) Monochromatic light of wavelength 589 nm is incident from air on a water surface. If μ for water is 1.33 , find the wavelength, frequency and speed of the refracted light.

(ii) A double convex lens is made of a glass of refractive index 1.55, with both faces of the same radius of curvature. Find the radius of curvature required, if the focal length is 20 cm.

U [OD I, II, III, 2016]

Ans. (i)

λ=589 nm133=4428 nm1/2

Frequency,

v=3×108 ms1589 nm

=5.09×1014 Hz

1/2

Speed

v=3×1081.33 m/s

(ii)

=225×108 m/s 1f=[μ2μ11][1R11R2] 120=[1.5511]2R R=(20×110)cm=22 cm 1/2

120=[1.5511]2R

R=(20×110)cm=22 cm

[CBSE Marking Scheme 2016]



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