SATHEE: Data Interpretation Ques 20

Data Interpretation

Data Interpretation Ques 20

Question-

Directions : The following table shows the details about the percentage distribution of students admitted in four different colleges for five different subjects. The table also consists of respective male and female ratio of all the students in each subject. Consider the following table and answer the questions given below :

Students $\rightarrow$	Physics	Chemistry	Commerce	History	Maths
Colleges $\downarrow$
$A$	$20 \%$	$15 \%$	$25 \%$	$20 \%$	$20 \%$
$B$	$15 \%$	$15 \%$	$15 \%$	$30 \%$	$25 \%$
$C$	$30 \%$	$20 \%$	$10 \%$	$20 \%$	$20 \%$
$D$	$25 \%$	$25 \%$	$10 \%$	$30 \%$	$10 \%$
Ratio between male and female	$2: 3$	$3: 2$	$1: 2$	$2: 1$	$1: 1$

Total students distribution among four colleges $A$, $B$, $C$ and $D$ is $2: 3: 3: 2$

If the total number of students admitted in college B is 600, what is the total male students’ strength in college C?

(1) 304

(2) 286

(3) 292

(4) 312

(5) 276

Show Answer

Answer: (1)

Solution: (1)

Ratio of students in all colleges $A$, $B$, $C$ and $D$ $=2: 3: 3: 2$

Total students in college $B$ $=600$

$\therefore$ Students in college C $=\left(\frac{600}{3}\right) \times 3=600$

Males in Physics $=600 \times 30 \% \times \frac{2}{5}$ $=\frac{600 \times 30 \times 2}{100 \times 5}=72$

Males in Chemistry $=600 \times 20 \% \times \frac{3}{5}=72$

Males in Commerce $=600 \times 10 \% \times \frac{1}{3}=20$

Males in History $=600 \times 20 \% \times \frac{2}{3}=80$

Males in Maths $=600 \times 20 \% \times \frac{1}{2}=60$

Total male students $=72+72+20+80+60=304$

Data Interpretation

Data Interpretation Ques 20

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Data Interpretation

Data Interpretation Ques 20

Table of Contents

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Mentorship

NCERT Exercise Video Solution

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