Work Energy And Power Question 288

Question: A bullet of mass 20g and moving with 600 m/s collides with a block of mass 4 kg hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision?

Options:

A) 200mA

B) 150 m/s

C) 400 m/s

D) 300 m7s

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Initial, $ K.E.=\frac{1}{2}mv^{2}=\frac{1}{2}\times \frac{20}{1000}\times 600\times 600 $ Change in $ K.E.=P.E. $

$ \frac{1}{2}m( v^{2}-v{{’}^{2}} )=mgh $

$ \Rightarrow 3600-\frac{1}{2}\times \frac{20}{1000}\times v_1^{2}=4\times 10\times 80 $

$ \Rightarrow {v_1}=200m/s $



NCERT Chapter Video Solution

Dual Pane