Work Energy And Power Question 288

Question: A bullet of mass 20g and moving with 600 m/s collides with a block of mass 4 kg hanging with the string. What is velocity of bullet when it comes out of block, if block rises to height 0.2 m after collision?

Options:

A) 200mA

B) 150 m/s

C) 400 m/s

D) 300 m7s

Show Answer

Answer:

Correct Answer: A

Solution:

[a] Initial, K.E.=12mv2=12×201000×600×600 Change in K.E.=P.E.

12m(v2v2)=mgh

360012×201000×v12=4×10×80

v1=200m/s



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