Work Energy And Power Question 211
Question: A force F acts on a particle such that its position x changes as shown in the figure. The work done by the particle as it moves from $ x=0 $ to 20 m is
Options:
A) 37.5 J
B) 10 J
C) 45 J
D) 22.5 J
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ W = area of F - x graph $
$ =areaof\Delta +areaofrectangle+areaof\Delta $
$ =\frac{5\times 3}{2}+10\times 3+\frac{5\times 3}{2}=45J $
