Work Energy And Power Question 211

Question: A force F acts on a particle such that its position x changes as shown in the figure. The work done by the particle as it moves from $ x=0 $ to 20 m is

Options:

A) 37.5 J

B) 10 J

C) 45 J

D) 22.5 J

Show Answer

Answer:

Correct Answer: C

Solution:

[c] $ W = area of F - x graph $

$ =areaof\Delta +areaofrectangle+areaof\Delta $

$ =\frac{5\times 3}{2}+10\times 3+\frac{5\times 3}{2}=45J $



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