Properties Of Solids And Liquids Question 78

Question: A hammer of mass 1kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is 0.105 cal/gm°C and half the energy is converted into heat, the raise in temperature of nail is [RPMT 1995]

Options:

A) 7.1°C

B) 9.2°C

C) 10.5°C

D) 12.1°C

Show Answer

Answer:

Correct Answer: A

Solution:

$ W=JQ $

therefore $ \frac{1}{2}( \frac{1}{2}Mv^{2} )=J(m.c.\Delta \theta ) $

therefore $ \frac{1}{4}\times 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ] $

therefore $ \Delta \theta =7.1{}^\circ C $



NCERT Chapter Video Solution

Dual Pane