Properties Of Solids And Liquids Question 78
Question: A hammer of mass 1kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is 0.105 cal/gm°C and half the energy is converted into heat, the raise in temperature of nail is [RPMT 1995]
Options:
A) 7.1°C
B) 9.2°C
C) 10.5°C
D) 12.1°C
Show Answer
Answer:
Correct Answer: A
Solution:
$ W=JQ $
therefore $ \frac{1}{2}( \frac{1}{2}Mv^{2} )=J(m.c.\Delta \theta ) $
therefore $ \frac{1}{4}\times 1\times {{(50)}^{2}}=4.2[200\times 0.105\times \Delta \theta ] $
therefore $ \Delta \theta =7.1{}^\circ C $
