Properties Of Solids And Liquids Question 429

Question: A hammer of mass 1 kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is $ 0.105 cal/gm{}^\circ C $ and half the energy is converted into heat. the raise in temperature of nail is

Options:

A) $ 7.1{}^\circ C $

B) $ 9.2{}^\circ C $

C) $ 10.5{}^\circ C $

D) $ 12.1{}^\circ C $

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Answer:

Correct Answer: A

Solution:

[a] $ W=JQ\Rightarrow \frac{1}{2}( \frac{1}{2}Mv^{2} )=J( m.c.\Delta \theta ) $

$ \frac{1}{4}\times 1\times {{( 50 )}^{2}}= 4.2[ 200\times 0.105\times \Delta \theta ] $

$ \Rightarrow \Delta \theta =7.1{}^\circ C $



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