Properties Of Solids And Liquids Question 429
Question: A hammer of mass 1 kg having speed of 50 m/s, hit a iron nail of mass 200 gm. If specific heat of iron is $ 0.105 cal/gm{}^\circ C $ and half the energy is converted into heat. the raise in temperature of nail is
Options:
A) $ 7.1{}^\circ C $
B) $ 9.2{}^\circ C $
C) $ 10.5{}^\circ C $
D) $ 12.1{}^\circ C $
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Answer:
Correct Answer: A
Solution:
[a] $ W=JQ\Rightarrow \frac{1}{2}( \frac{1}{2}Mv^{2} )=J( m.c.\Delta \theta ) $
$ \frac{1}{4}\times 1\times {{( 50 )}^{2}}= 4.2[ 200\times 0.105\times \Delta \theta ] $
$ \Rightarrow \Delta \theta =7.1{}^\circ C $
