Properties Of Solids And Liquids Question 403
Question: On a linear temperature scale Y, water freezes at $ 160{}^\circ Y $ and boils at $ - 50{}^\circ Y $ . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)
Options:
A) $ -73.7{}^\circ Y $
B) $ -233.7{}^\circ Y $
C) $ -86.3{}^\circ Y $
D) $ -106.3{}^\circ Y $
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Answer:
Correct Answer: C
Solution:
[c] $ \frac{Readingonanyscale-LFP}{UFP-LFP} $ =constant for all scales $ \frac{340-273}{373-273}=\frac{{}^\circ y-( -160 )}{-50-( -160 )}\Rightarrow \frac{67}{100}=\frac{y+160}{110} $
$ \therefore y=-86.3{}^\circ Y $
