Properties Of Solids And Liquids Question 403

Question: On a linear temperature scale Y, water freezes at $ 160{}^\circ Y $ and boils at $ - 50{}^\circ Y $ . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)

Options:

A) $ -73.7{}^\circ Y $

B) $ -233.7{}^\circ Y $

C) $ -86.3{}^\circ Y $

D) $ -106.3{}^\circ Y $

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Answer:

Correct Answer: C

Solution:

[c] $ \frac{Readingonanyscale-LFP}{UFP-LFP} $ =constant for all scales $ \frac{340-273}{373-273}=\frac{{}^\circ y-( -160 )}{-50-( -160 )}\Rightarrow \frac{67}{100}=\frac{y+160}{110} $

$ \therefore y=-86.3{}^\circ Y $



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