SATHEE: Properties Of Solids And Liquids Question 403

Properties Of Solids And Liquids Question 403

Question: On a linear temperature scale Y, water freezes at $160^{\circ} Y$ and boils at $- 50^{\circ} Y$ . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)

Options:

A) $- 73.7^{\circ} Y$

B) $- 233.7^{\circ} Y$

C) $- 86.3^{\circ} Y$

D) $- 106.3^{\circ} Y$

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Answer:

Correct Answer: C

Solution:

[c] $\frac{R e a d i n g o n a n y s c a l e - L F P}{U F P - L F P}$ =constant for all scales $\frac{340 - 273}{373 - 273} = \frac{^{\circ} y - (- 160)}{- 50 - (- 160)} \Rightarrow \frac{67}{100} = \frac{y + 160}{110}$

$∴ y = - 86.3^{\circ} Y$

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Properties Of Solids And Liquids Question 403

Question: On a linear temperature scale Y, water freezes at $160^{\circ} Y$ and boils at $- 50^{\circ} Y$ . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)

Options:

Answer:

Solution:

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Properties Of Solids And Liquids Question 403

Question: On a linear temperature scale Y, water freezes at 160∘Y and boils at −50∘Y . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: On a linear temperature scale Y, water freezes at $160^{\circ} Y$ and boils at $- 50^{\circ} Y$ . On this Y scale, a temperature of 340 K would be read as : (water freezes at 273 K and boils at 373 K)