Properties Of Solids And Liquids Question 391

Question: 4200 J of work is required for

Options:

A) increasing the temperature of 10 g of water through $ 10{}^\circ C $

B) increasing the temperature of 100 g of water through $ 10{}^\circ C $

C) increasing the temperature of 1 kg of water through $ 10{}^\circ C $

D) increasing the temperature of 500 g of water through $ 10{}^\circ C $

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Answer:

Correct Answer: B

Solution:

[b] Work done to raise the temperature of 100 gm water through $ 10{}^\circ C $ is $ W=JQ =4.2\times (100\times l{{0}^{-3}}\times 1000\times l0) $

$ =4200J $



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