Properties Of Solids And Liquids Question 391
Question: 4200 J of work is required for
Options:
A) increasing the temperature of 10 g of water through $ 10{}^\circ C $
B) increasing the temperature of 100 g of water through $ 10{}^\circ C $
C) increasing the temperature of 1 kg of water through $ 10{}^\circ C $
D) increasing the temperature of 500 g of water through $ 10{}^\circ C $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] Work done to raise the temperature of 100 gm water through $ 10{}^\circ C $ is $ W=JQ =4.2\times (100\times l{{0}^{-3}}\times 1000\times l0) $
$ =4200J $
