Properties Of Solids And Liquids Question 312

Question: A capillary tube of radius r is dipped in a liquid of density r and surface tension S. If the angle of contact is q, the pressure difference between the two surfaces in the beaker and the capillary

Options:

A) $ \frac{S}{r}\cos \theta $

B)$ \frac{2S}{r}\cos \theta $

C) $ \frac{S}{r\cos \theta } $

D) $ \frac{2S}{r\cos \theta } $

Show Answer

Answer:

Correct Answer: B

Solution:

$ S=\frac{rhdg}{2\cos \theta }\Rightarrow $ Pressure difference $ =hdg=\frac{2S}{r}\cos \theta $



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