Properties Of Solids And Liquids Question 312
Question: A capillary tube of radius r is dipped in a liquid of density r and surface tension S. If the angle of contact is q, the pressure difference between the two surfaces in the beaker and the capillary
Options:
A) $ \frac{S}{r}\cos \theta $
B)$ \frac{2S}{r}\cos \theta $
C) $ \frac{S}{r\cos \theta } $
D) $ \frac{2S}{r\cos \theta } $
Show Answer
Answer:
Correct Answer: B
Solution:
$ S=\frac{rhdg}{2\cos \theta }\Rightarrow $ Pressure difference $ =hdg=\frac{2S}{r}\cos \theta $
