Properties Of Solids And Liquids Question 271

Question: The fraction of a floating object of volume V0 and density d0 above the surface of a liquid of density d will be

Options:

A)d0d

B)dd0d+d0

C)dd0d

D)dd0dd0

Show Answer

Answer:

Correct Answer: C

Solution:

For the floatation V0d0g=Vin d g

therefore Vin=V0d0d Vout=V0Vin=V0V0d0d

=V0[dd0d]

therefore VoutV0=dd0d.



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