Properties Of Solids And Liquids Question 271
Question: The fraction of a floating object of volume $ V _{0} $ and density $ d _{0} $ above the surface of a liquid of density d will be
Options:
A)$ \frac{d _{0}}{d} $
B)$ \frac{dd _{0}}{d+d _{0}} $
C)$ \frac{d-d _{0}}{d} $
$ $
D)$ \frac{dd _{0}}{d-d _{0}} $
Show Answer
Answer:
Correct Answer: C
Solution:
For the floatation $ V _{0}d _{0}g=V _{in}\ d\ g $
therefore $ V _{in}=V _{0}\frac{d _{0}}{d} $ $ V _{out}=V _{0}-V _{in}=V _{0}-V _{0}\frac{d _{0}}{d} $
$ =V _{0}\left[ \frac{d-d _{0}}{d} \right] $
therefore $ \frac{V _{out}}{V _{0}}=\frac{d-d _{0}}{d}. $
