Properties Of Solids And Liquids Question 271

Question: The fraction of a floating object of volume $ V _{0} $ and density $ d _{0} $ above the surface of a liquid of density d will be

Options:

A)$ \frac{d _{0}}{d} $

B)$ \frac{dd _{0}}{d+d _{0}} $

C)$ \frac{d-d _{0}}{d} $

$ $

D)$ \frac{dd _{0}}{d-d _{0}} $

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Answer:

Correct Answer: C

Solution:

For the floatation $ V _{0}d _{0}g=V _{in}\ d\ g $

therefore $ V _{in}=V _{0}\frac{d _{0}}{d} $ $ V _{out}=V _{0}-V _{in}=V _{0}-V _{0}\frac{d _{0}}{d} $

$ =V _{0}\left[ \frac{d-d _{0}}{d} \right] $

therefore $ \frac{V _{out}}{V _{0}}=\frac{d-d _{0}}{d}. $



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