Physics And Measurement Question 96
Question: Dimensional formula of magnetic flux is
[ CBSE PMT 1989, 99; DPMT 2001; Kerala PMT 2005]
Options:
A) $ ML^{2}{{T}^{-2}}{{A}^{-1}} $
B) $ ML^{0}{{T}^{-2}}{{A}^{-2}} $
C) $ M^{0}{{L}^{-2}}{{T}^{-2}}{{A}^{-3}} $
D) $ ML^{2}{{T}^{-2}}A^{3} $
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Answer:
Correct Answer: A
Solution:
$ \varphi =BA=\frac{F}{I\times L}A=\frac{[ML{{T}^{-2}}][L^{2}]}{[A][L]}=[ML^{2}{{T}^{-2}}{{A}^{-1}}] $
