Physics And Measurement Question 96

Question: Dimensional formula of magnetic flux is

[ CBSE PMT 1989, 99; DPMT 2001; Kerala PMT 2005]

Options:

A) $ ML^{2}{{T}^{-2}}{{A}^{-1}} $

B) $ ML^{0}{{T}^{-2}}{{A}^{-2}} $

C) $ M^{0}{{L}^{-2}}{{T}^{-2}}{{A}^{-3}} $

D) $ ML^{2}{{T}^{-2}}A^{3} $

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Answer:

Correct Answer: A

Solution:

$ \varphi =BA=\frac{F}{I\times L}A=\frac{[ML{{T}^{-2}}][L^{2}]}{[A][L]}=[ML^{2}{{T}^{-2}}{{A}^{-1}}] $



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