Physics And Measurement Question 88
Question: The dimensions of physical quantity $ X $ in the equation Force $ =\frac{X}{Density} $ is given by
[DCE 1993]
Options:
A) $ M^{1}L^{4}{{T}^{-2}} $
B) $ M^{2}{{L}^{-2}}{{T}^{-1}} $
C) $ M^{2}{{L}^{-2}}{{T}^{-2}} $
D) $ M^{1}{{L}^{-2}}{{T}^{-1}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[X] = [F] × [r] = $ [ML{{T}^{-2}}]\times [ \frac{M}{L^{3}} ]=[M^{2}{{L}^{-2}}{{T}^{-2}}] $
