Physics And Measurement Question 88

Question: The dimensions of physical quantity $ X $ in the equation Force $ =\frac{X}{Density} $ is given by

[DCE 1993]

Options:

A) $ M^{1}L^{4}{{T}^{-2}} $

B) $ M^{2}{{L}^{-2}}{{T}^{-1}} $

C) $ M^{2}{{L}^{-2}}{{T}^{-2}} $

D) $ M^{1}{{L}^{-2}}{{T}^{-1}} $

Show Answer

Answer:

Correct Answer: C

Solution:

[X] = [F] × [r] = $ [ML{{T}^{-2}}]\times [ \frac{M}{L^{3}} ]=[M^{2}{{L}^{-2}}{{T}^{-2}}] $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक