Physics And Measurement Question 55

Question: The dimensional formula for the modulus of rigidity is

[MNR 1984; IIT 1982; MP PET 2000]

Options:

A) $ ML^{2}{{T}^{-2}} $

B) $ M{{L}^{-1}}{{T}^{-3}} $

C) $ M{{L}^{-2}}{{T}^{-2}} $

D) $ M{{L}^{-1}}{{T}^{-2}} $

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Answer:

Correct Answer: D

Solution:

Modulus of rigidity = $ \frac{Shear\ stress}{Shear\ strain}= $

$ [M{{L}^{-1}}{{T}^{-2}}] $



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