Physics And Measurement Question 55
Question: The dimensional formula for the modulus of rigidity is
[MNR 1984; IIT 1982; MP PET 2000]
Options:
A) $ ML^{2}{{T}^{-2}} $
B) $ M{{L}^{-1}}{{T}^{-3}} $
C) $ M{{L}^{-2}}{{T}^{-2}} $
D) $ M{{L}^{-1}}{{T}^{-2}} $
Show Answer
Answer:
Correct Answer: D
Solution:
Modulus of rigidity = $ \frac{Shear\ stress}{Shear\ strain}= $
$ [M{{L}^{-1}}{{T}^{-2}}] $
